Example: Using JSON_AGG without GROUP BY and with Parameter Names - Advanced SQL Engine - Teradata Database

The example shows how to use JSON_Agg to assign parameter names in the resulting JSON object.

SELECT JSON_agg(empID AS id, company, empName AS name, empAge AS age) 
FROM emp_table;

Result:

JSON_agg
--------
{ "id" : 1, "company" : "Teradata", "name" : "Cameron", "age" : 24 },
{ "id" : 2, "company" : "Teradata", "name" : "Justin", "age" : 34 },
{ "id" : 3, "company" : "Teradata", "name" : "Someone", "age" : 24 }