td_month_of_year
Purpose
Returns the number of months from the beginning of the year (January 1st) to the specified date.
Syntax
where:
Syntax element… |
Specifies… |
SYSLIB |
the name of the database where the function is located. |
expression |
an expression that results in a DATE, TIMESTAMP, or TIMESTAMP WITH TIME ZONE value. |
ANSI Compliance
This is a Teradata extension to the ANSI SQL:2011 standard.
Argument Types
td_month_of_year is an overloaded scalar function. It is defined with the following parameter data types:
If the argument passed to the function does not match one of these declared data types, an error is returned indicating that the function does not exist.
For more information on overloaded functions, see “Function Name Overloading” in SQL External Routine Programming.
Result
The result is an INTEGER value from 1 to 12.
Usage Notes
The td_month_of_year function provides improved performance compared to using the Sys_Calendar.Calendar system view to obtain similar results.
For more information about the CALENDAR system view, see Data Dictionary.
Example
If the current date is August 29, 2010, the following queries return the value 8 as the result because August 29, 2010 falls on the 8th month of the year.
SELECT td_month_of_year(CURRENT_DATE);
SELECT td_month_of_year(DATE '2010-08-29');