17.00 - 17.05 - Example: Calculating the Difference in Days Between DATE Values - Advanced SQL Engine - Teradata Database

Teradata Vantage™ - SQL Date and Time Functions and Expressions

Product
Advanced SQL Engine
Teradata Database
Release Number
17.00
17.05
Release Date
June 2020
Content Type
Programming Reference
Publication ID
B035-1211-170K
Language
English (United States)

The following query calculates the difference in days between the two DATE values.

SELECT (DATE '2007-05-10' - DATE '2007-04-28') DAY;

The result is the following:

(2007-05-10 - 2007-04-28) DAY
-----------------------------
12

The following query calculates the difference in months between the two DATE values.

SELECT (DATE '2007-05-10' - DATE '2007-04-28') MONTH;

The result is the following:

(2007-05-10 - 2007-04-28) MONTH
-------------------------------
1

There is a difference of 12 days between the two dates, which does not constitute one month. However, Teradata Database ignores the day values during the calculation and only considers the month values, so the result is an interval of one month indicating the difference between April and May.