例: JSON_COMPOSEを使用して、テーブルから値を抽出し、JSONオブジェクトを作成 - Advanced SQL Engine - Teradata Database

JSON_COMPOSEを使用して、テーブルから選択した値からJSONオブジェクトを作成します。

SELECT JSON_Compose(T.company, T.employees)
FROM
 (
  SELECT company, JSON_agg(empID AS id, 
     empName AS name, 
     empAge AS age) AS employees
  FROM emp_table
  GROUP BY company
 ) AS T;

結果:

JSON_Compose
------------
{
  "company" : "Teradata",
  "employees" : [ 
     { "id" : 1, "name" : "Cameron", "age" : 24 },
     { "id" : 2, "name" : "Justin", "age" : 34 }
  ]
}
{
  "company" : "Apple",
  "employees" : [ 
     { "id" : 3, "name" : "Someone", "age" : 24 } 
  ]
}