PERCENTILE Function Examples | Teradata Vantage - Examples - Advanced SQL Engine - Teradata Database

Time Series Tables and Operations

Product
Advanced SQL Engine
Teradata Database
Release Number
17.05
17.00
Published
June 2020
Language
English (United States)
Last Update
2021-01-22
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cxa1555383531762.ditamap
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dita:id
B035-1208
lifecycle
previous
Product Category
Teradata Vantageā„¢

Example: Using PERCENTILE

/*PTI Table*/
SELECT $TD_TIMECODE_RANGE, $TD_GROUP_BY_TIME, BUOYID, PERCENTILE(TEMPERATURE, 25), COUNT(*)
FROM OCEAN_BUOYS
WHERE TD_TIMECODE BETWEEN TIMESTAMP '2014-01-06 08:00:00' AND TIMESTAMP '2014-01-06 10:30:00'
GROUP BY TIME (MINUTES(10) AND BUOYID)
ORDER BY 3,2,1;

/*Non-PTI Table*/
SELECT $TD_TIMECODE_RANGE, $TD_GROUP_BY_TIME, BUOYID, PERCENTILE(TEMPERATURE, 25), COUNT(*)
FROM OCEAN_BUOYS_NONPTI
WHERE TIMECODE BETWEEN TIMESTAMP '2014-01-06 08:00:00' AND TIMESTAMP '2014-01-06 10:30:00'
GROUP BY TIME (MINUTES(10) AND BUOYID)
USING TIMECODE(TIMECODE)

The results are the same for both tables:

TIMECODE_RANGE GROUP BY TIME (MINUTES(10)) BUOYID Percentile (TEMPERATURE) Count(*)
('2014-01-06 08:00:00.000000+00:00', '2014-01-06 08:10:00.000000+00:00') 1 0 10 3
('2014-01-06 08:10:00.000000+00:00', '2014-01-06 08:20:00.000000+00:00') 2 0 10 2
('2014-01-06 09:00:00.000000+00:00', '2014-01-06 09:10:00.000000+00:00') 7 1 72 6
('2014-01-06 10:00:00.000000+00:00', '2014-01-06 10:10:00.000000+00:00') 13 44 43 10
('2014-01-06 10:10:00.000000+00:00', '2014-01-06 10:20:00.000000+00:00') 14 44 43 1

Example: Using the LOW Interpolation Scheme

/*PTI Table*/
SELECT $TD_TIMECODE_RANGE, $TD_GROUP_BY_TIME, BUOYID, PERCENTILE(TEMPERATURE, 25, LOW), COUNT(*)
FROM OCEAN_BUOYS
WHERE TD_TIMECODE BETWEEN TIMESTAMP '2014-01-06 08:00:00' AND TIMESTAMP '2014-01-06 10:30:00'
GROUP BY TIME (MINUTES(10) AND BUOYID)
ORDER BY 3,2,1;

/*Non-PTI Table*/
SELECT $TD_TIMECODE_RANGE, $TD_GROUP_BY_TIME, BUOYID, PERCENTILE(TEMPERATURE, 25, LOW), COUNT(*)
FROM OCEAN_BUOYS_NONPTI
WHERE TIMECODE BETWEEN TIMESTAMP '2014-01-06 08:00:00' AND TIMESTAMP '2014-01-06 10:30:00'
GROUP BY TIME (MINUTES(10) AND BUOYID)
USING TIMECODE(TIMECODE)
ORDER BY 3,2,1;

The results are the same for both tables:

TIMECODE_RANGE GROUP BY TIME (MINUTES(10)) BUOYID Percentile (TEMPERATURE) Count(*)
('2014-01-06 08:00:00.000000+00:00', '2014-01-06 08:10:00.000000+00:00') 1 0 10 3
('2014-01-06 08:10:00.000000+00:00', '2014-01-06 08:20:00.000000+00:00') 2 0 10 2
('2014-01-06 09:00:00.000000+00:00', '2014-01-06 09:10:00.000000+00:00') 7 1 72 6
('2014-01-06 10:00:00.000000+00:00', '2014-01-06 10:10:00.000000+00:00') 13 44 44 43
('2014-01-06 10:10:00.000000+00:00', '2014-01-06 10:20:00.000000+00:00') 14 44 43 1